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96x^2+264x+108=0
a = 96; b = 264; c = +108;
Δ = b2-4ac
Δ = 2642-4·96·108
Δ = 28224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{28224}=168$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(264)-168}{2*96}=\frac{-432}{192} =-2+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(264)+168}{2*96}=\frac{-96}{192} =-1/2 $
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